Подскажите как решить номер 68

1) (1/3^4)^(-3/4)+(1/3^3)^(-4/3)=(1/3^(-12))^1/4+(1/3^(-12))^(1/3)=3^3+3^4=108

2) (0.2)^(-3)-(0.5)^(-2)=(1/5)^(-3)-(1/2)^(-2)=5^3-2^2=121

3) (10^9/10^2)^(1/7)-(5^6/5^4)^(1/5)=10-5^(2/5)

4) 5^2+(1/5)^((-4)*3/4)=25+(1/5)^(-3)=25+125=150